My Bash script looks like this: #!/bin/bash java -cp '$HOME/myapp' abc $CAJA_SCRIPT_SELECTED_FILE_PATHS Explanations: Since my program was placed inside here: /home/john/myapp/abc.class • I must always use -cp java options to locate my 'abc' program first. Informations you might need: • java: usr/bin/java • abc Java program: home/john/myapp/abc.class • The script will be put inside home/john/.config/caja/scripts • The john is my username for Linux Mint MATE 17.2, with caja as file manager Below questions might close to my problem: • • •. An script.sh for running a java program on mac download. • The $HOME represents my home directory, /home/john, • The $CAJA_SCRIPT_SELECTED_FILE_PATHS environment variable represents the path of the folder I selected, which eventually being passed as argument to 'abc' program. How my Bash script will look like? That Java program need ' directory path' of that chosen folder, as argument.
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